The 3.1-Mg pickup truck is towing the 1.6-Mg car using a cable as shown Part A (
ID: 2038853 • Letter: T
Question
The 3.1-Mg pickup truck is towing the 1.6-Mg car using a cable as shown Part A (Figure 1) If the car is initially at rest and the truck is coasting with a velocity of 30 km/h when the cable is slack, determine the common velocity of the truck and the car just after the cable becomes taut. Express your answer to three significant figures and include the appropriate units View Available Hint(s) Value Units Submit Part B Figure 1 of 1 Also, find the loss of energy Express your answer to three significant figures and include the appropriate units View Available Hint(s) 30 km/h AB-1 Value | Units | SubmitExplanation / Answer
(A) Applying momentum conservation for two car system,
(3.1 v) + (1.6 x 0) = (3.1 + 1.6)(30)
v = 45.5 km/h .....Ans
(B) v = 45.5 x 1000 m / 3600 s = 12.63 m/s
vf = 30 x 1000 m / 3600 s = 8.33 m/s
Ei = (3.1 x 12.63^2 / 2 )+ (1.6 x 0) = 247.6 kJ
Ef = (3.1 + 1.6) (8.333^2)/2 = 163.2 kJ
delta(E) = Ei - Ef = 84.4 kJ Or 84.4 x 10^3 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.