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Sort Number Chapter 30.3-4 Last name First Name )Remember the right hand rule sh

ID: 2038812 • Letter: S

Question

Sort Number Chapter 30.3-4 Last name First Name )Remember the right hand rule shown in Figure 30.9. If there is a steady current into the page, there is clockwise looping B field surrounding the current Remember the right hand rule shown in Figure 30.9. If there is a steady current into the page, there is count clockwise looping B field surrounding the current. ) Magnetic field lines have no beginning and no end. They form closed loop. Magnetic field lines have no beginning and no end. They form closed loop. Electric field lines due to static charges begin on positive charges and end on negative charges. ) Electric field lines due to static charges form closed loop. ) Recall chapser 25. For static electrical field due to static charges, the electrical potential difference between two points B and A is defined as the following. If A and B are the same point, the potential at A and B are the same, which means that the path integral of the E dot ds along a closed loop (returning to its initial point) is equal to zcro. ) The path integral ori dot dg along a closed loop (returning to its initial point) is always equal to zero. The path integral of B dot dš along a closed loop, which exactly follows a B field line loop won't be zero. ( The path integral of B dot d3 along a closed path, depends on the total current passing through the bounded by the closed path. ( ) If a closed loop doesn't current, the path integral of dot di along this closed path is zero. When B and dš are in the same direction dot dš is simply equal to Bds, because the cos (0)-1. (The angle between B and dš is zero.) ( ) when and dy are in the same direction dot dis zero, because the sin (0)-?.The angle between and dis zero.) ( ) when ?? and d, are perpendicular to each other, ?? dot dS is simply equal to Bds, because the sin (90). (The angle between B and dš is 90 degree.) When B and dš are perpendicular to each other, B dot dš is zero, because the cos (90)-0.(The angle between B and dš is 90 degree.) In order to apply Ampere's law for simple calculation of the B field, surrounding a cylindrical wire carrying a steady current, we should choose an integral path of a square In order to apply Ampere's law for simple calculation of the B field, surrounding a cylindrical wire carrying a steady current, we should choose an integral path of a circle. center of the wire. the center of the wire. ) Outside a cylindrical wire carrying a steady current, the B field strength reduces as I/r, where r is the distance to the Outside a cylindrical wire carrying a steady current, the B field strength reduces as l/r, where r is the distance to The circumference of a circle with radius r, is The area of a circle with radius r, is The surface area of a sphere with radius r, is The volume of a sphere with radius r, is A small cirele's radius is t. A big circle's radius is R. The ratio of the two circle's area is Anail An /R. A small circle's radius is r'. A big circle's radius is r. The ratio of the two circle's area is A/R t/R For a toroid shown here, if the wires are densely packed, the B field inside the toroid follows the dashed line and the arrows of B. The total amount of current passing through the dashed closed loop is I The total amount of current passing through the dashed closed loop is 181 )The total amount of current passing through the dashed closed loop is 141 A toroid can be used to produce a reasonably uniform magnetic field

Explanation / Answer

TRUE

TRUE

TRUE . Magnetic field has no beginning and ending. They form closed loops. This is because there is no existence of magnetic monopole.

TRUE

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