floor, a worker of weight 0.800 kN pushes horizontally with a force of 0.300 kN
ID: 2038726 • Letter: F
Question
floor, a worker of weight 0.800 kN pushes horizontally with a force of 0.300 kN on a box weighing 1.80 kN. As a result of this push, find the magnitude acceleration of the worker and the box. 3) Two blocks are connected by a string that goes over an ideal pulley as shown in the figure. Block A has a mass of 4.00 kg and can slide over a rough plane inclined 30.0° to the horizontal. The coefficient of kinetic friction between block A and the plane is 0.400. Block B has a mass of 3.00 kg. What is the acceleration of the blocks?Explanation / Answer
2)Mass of worker = 800 N/9.81 = 81.55 kg
mass of box = 1800/9.81 = 183.49 kg
Fnet = 300 N
a(worker) = 300/81.55 = 3.68 m/s^2
a(box) = 300/183.49 = 1.63 m/s^2
Hence, a(worker) = 3.68 m/s^2 ; a(box) = 1.63 m/s^2
3)We can write for the hanging mass:
mBg - T = mB a
for mass on incline
T - mAg sin(theta) - uk mB g cos(theta) = mA a
from the above two eqn we get
a = (mB g - mA g sin(theta) - uk mB g cos(theta))/(mA + mB)
a = (3 x 9.81 - 4 x 9.81 x sin30 - 0.4 x 4 x 9.81 x cos30)/(3 + 4) = -0.54 m/s^2
Hence, a = -0.54 m/s^2
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