Observer A on Earth sees spaceship B moving at speed v = 0.600 c 0 away from Ear
ID: 2038394 • Letter: O
Question
Observer A on Earth sees spaceship B moving at speed v = 0.600c0 away from Earth and spaceship C moving at the same speed in the opposite direction. Observer A determines that both ships simultaneously sent out a radio signal at 12:00:00 noon and another signal at 12:05:00 p.m., making the time interval A measures between the emission of the signals from each ship ?tA = 5.00 min . Let ?tBB denote the time interval measured on ship B between the emission of signals on ship B , ?tBC denote the time interval measured on ship B between the emission of signals on ship C , and ?tCB denote the time interval measured on ship C between emission of signals on ship B .
A). Is ?tBB greater than, less than, or equal to ?tA ?
B). Is ?tBC greater than, less than, or equal to ?tCB ?
Explanation / Answer
b is the correct anser .why because bb is moving in circular motion ,as ta only having stright line path .so a object moving in a circular motion having more lenth compared to be in staright line path
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