.\'Il Sprint? 12:14 PM a session.masteringphysics.com ?Ch 28 3of4 An electron mo

Question

.'Il Sprint? 12:14 PM a session.masteringphysics.com ?Ch 28 3of4 An electron moves at 0.100 c as shown in the figure. There are points: A. B. C. and D 240 ??? from the electron. 60° Electron 60° -Part A Find the magnitude of the magnetic field this electon produces at the point A Part B This question will be shown after you complete previous question(s). Part C Find the magnitude of the magnetic field this electon produces at the point B Request Answer Part D This question will be shown after you complete previous question(s). Part E Find the magnitude of the magnetic field this electon produces at the point C

Explanation / Answer

A) magnetic field at point A,

B_A = (mue/(4*pi))*(q*v*sin(theta))/r^2

= (4*pi*10^-7/(4*pi))*(1.6*10^-19*0.1*3*10^8*sin(30))/(2.4*10^-6)^2

= 4.17*10^-8 T

C) magnetic field at point B,

B_B = (mue/(4*pi))*(q*v*sin(theta))/r^2

= (4*pi*10^-7/(4*pi))*(1.6*10^-19*0.1*3*10^8*sin(150))/(2.4*10^-6)^2

= 4.17*10^-8 T

E) magnetic field at point C,

B_C = (mue/(4*pi))*(q*v*sin(theta))/r^2

= (4*pi*10^-7/(4*pi))*(1.6*10^-19*0.1*3*10^8*sin(90))/(2.4*10^-6)^2

= 8.33*10^-8 T

G) magnetic field at point D,

B_D = (mue/(4*pi))*(q*v*sin(theta))/r^2

= (4*pi*10^-7/(4*pi))*(1.6*10^-19*0.1*3*10^8*sin(180))/(2.4*10^-6)^2

= 0 T

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