1 Inelastic collision Two carts appronch each other. One, with mass 690 g travel
ID: 2038114 • Letter: 1
Question
1 Inelastic collision Two carts appronch each other. One, with mass 690 g travels right with speed 1.8m/s and the other with mass 550g travels left with speed 2.0m/s a) Determine the magnitude of the total momentum of the system of carts 40) Cr)550g)(2.0) b) The carts stick and move together after colliding. In which direction will they move after the collision? Explain your answer. 2 Cart "explosion" Two carts of different masses are initially held together and at rest. Cart 1 has mass my and cart 2 has mass m2m A spring release plunger on the carts triggered. causing the carts to move apart. How is the speed of cart 2 related to that of cart h after the plunger has been triggered? Explain your answer.Explanation / Answer
1)
let m1 = 690 grams = 0.69 kg
v1 = 1.8 m/s
m2 = 550 grams = 0.55 kg
v2 = -2 m/s
a) P_total = m1*v1 + m2*v2
= 0.69*1.8 + 0.55*(-2)
= 0.142 kg.m/s
b) let v is the final speed of both cars after the collsion.
apply conservation of momentum
(m1 + m2)*v = m1*v1 + m2*v2
v = (m1*v1 + m2*v2)/(m1 + m2)
= (0.69*1.8 + 0.55*(-2))/(0.69 + 0.55)
= 0.114 m/s
v is positive means the cars move towards right
2) momentum gained by cart 2 = momentum geined cart 1 in the opposite direction
m2*v2 = m1*v1
(m1/2)*v2 = m1*v1
v2 = 2*v1
the speed of cart 2 is two times of speed of cart1
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