9) You are trying to determine the coefficient of kinetic friction between a tab
ID: 2037878 • Letter: 9
Question
9) You are trying to determine the coefficient of kinetic friction between a table and a small 2.0 kg weight. You attach a spring of stiffness 2.5 N/cm to the weight and steadily slide the weight across the table. The spring stretches by 2.0 cm. How much force does this indicate you applied to the weight?
Correct, computer gets: 5.00 N
Hint: How do simple elastic forces work?
10) What is the coefficient of kinetic friction?
Correct, computer gets: 0.26
Hint: What's the relationship between the force you applied and the kinetic friction?
11) You slide the weight all the way to one edge of the table. You go to the other end and push the table. The coefficient of static friction between the weight and the table is 0.46. What is the maximum you can accelerate the table without causing the weight to slide?
Correct, computer gets: 4.46 m/s^2
Hint: What is the model for static friction force?
12) Suppose that you increase the table's acceleration to 6 m/s2. What is the weight's rate of acceleration?
Answer: Last Answer: 2.178 m/s^2 Not yet correct, tries 3/25
Hint: What force or forces are causing the the weight to accelerate?
Explanation / Answer
12) when acceleration (6 m/s^2) is greater than 4.46 m/s^2 the block slides on table in backward direction.
kinetic friction, fk = mue_k*N
m*a = mue_k*m*g
a = mue_k*g
= 0.26*9.8
= 2.548 m/s^2 (with repsect to ground) <<<<<<<----Answer
acceleration with respect to table = 2.548 - 6
= -3.452 m/s^2 (with repect to table)
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