(25%) Problem 4 n a ballistic penduluin dernon tration gone bad a 0 55 g ar gun
ID: 2037863 • Letter: #
Question
(25%) Problem 4 n a ballistic penduluin dernon tration gone bad a 0 55 g ar gun pellet, fired horizontally with kinetic energy 3.75 J, passes straight through the 430 g Styrofoam pendulum block. If the pendulum swung to a maximum height of 0.45 mm. how much kinetic energy did the pellet have after it emerged from the Styrofoam? Assume the pellet-block system is isolated: no FBD or IST is required for this problem. 50% Part (a) Please select the the correct equation that describes the kinetic energy for the pellet after the collision. Treat the interaction between the pellet and block as an inelastic collision, where the bullet interacts with the block for such a short period of time that you can treat the bullet as not deviating from it's original path. Grade Summary 0% 100% Potential /n 2m 2mp Submissions Attempts remaining: s (20% per attempt) detailed view 2m, mp 2m Submit Hint I give up Hits: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 50% Part (b) Solve numerically for the value of the amount of kinetic energy that the pellet has after the collision in JExplanation / Answer
4) 6th option is the correct answer.
Apply conservation of momentum
mp*vo = mp*vp + mb*vb
mp*vp = mp*vo - mb*vb
sqrt(2*mp*kp) = sqrt(2*mp*ko) - mb*sqrt(2*g*delta_h)
2*mp*kp = ( sqrt(2*mp*ko) - mb*sqrt(2*g*delta_h) )^2
kp = ( sqrt(2*mp*ko) - mb*sqrt(2*g*delta_h) )^2/(2*mp)
b) kp = ( sqrt(2*0.55*10^-3*3.75) - 0.43*sqrt(2*9.8*0.45*10^-3) )^2/(2*0.55*10^-3)
= 0.517 J
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