You have two light bulbs of different power and color, as indicated in the figur

Q: You have two light bulbs of different power and color, as indicated in the figur

a) red blue b) P = E / t = n h c / lambda t n/t = lampda * p / h c number of photons per red bulb = (650 * 10-9 * 180) / (6.63 * 10-34 * 3 * 108) = 5.88 * 1020 J/s number of photons per blue bulb = (460 * 10-9 * 35) / (6.63 * 10-34 * 3 * 108) = 8.09 * 1019 J/s

ID: 2037853 • Letter: Y

Question

You have two light bulbs of different power and color, as indicated in the figure. One is a Pi = 180-w red bulb, and the other is a P2 = 35-W blue bulb. (Take ,ed GMAIL chrome://newtab/ blue 460 nm.) (a) Which bulb emits more photons per second? red blue (b) Which bulb emits photons of higher energy? red blue (c) Calculate the number of photons emitted per second by each bulb. red bulb 4.183e-45x Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. photons/s 8.099 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. photons/s blue bulb

Explanation / Answer

a) red

blue

b) P = E / t = n h c / lambda t

n/t = lampda * p / h c

number of photons per red bulb = (650 * 10-9 * 180) / (6.63 * 10-34 * 3 * 108)

= 5.88 * 1020 J/s

number of photons per blue bulb = (460 * 10-9 * 35) / (6.63 * 10-34 * 3 * 108)

= 8.09 * 1019 J/s

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You have two lenses at your disposal one with a focal lenght F1=35.5 cm , the ot

You have two lightbulbs or different power and color, as indicated in (Figure 1)

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You have two light bulbs of different power and color, as indicated in the figur

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