(10%) Problem 5: A 0.240-kg billiard ball that is moving at 2.95 m/s in the posi
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(10%) Problem 5: A 0.240-kg billiard ball that is moving at 2.95 m/s in the positive direction strikes the bumper of a pool table and bounces straight back at 2.35 m/s. The collision lasts 0.0150 s > 33% Part (a) Calculate the component of the average force along the direction of the original motion, in newtons, that is exerted on the ball by the bumper during the collision Grade Summary Deductions Potential 4% 96% ave sin) cotanOasinO atan)acotan( cosh)tanh) tan): acosO sinh) Submissions Attempts remaining: 2 (4% per attempt) detailed view cosO 4% cotanh) END Degrees Radians BA DEL CLEAR Submit Hint Feedback give up Hints: 3% deduction per hint. Hints remaining: 2 Feedback: 5 % deduction per feedback. 33% Part (b) What is the change in kinetic energy, in joules, during the collision? 33% Part (c) What percent of the initial kinetic energy remains in the system after the collision?Explanation / Answer
(a) F = m?v / ?t = 0.240kg * (-2.35m/s - 2.95m/s) / 0.0150s = -84.8 N
(against the original direction of motion)
(b) initial KE = ½mv² = ½ * 0.240kg * (2.95m/s)² = 1.0443 J
final KE = ½ * 0.24kg * (2.35m/s)² = 0.6627 J
Lost KE = 0.3816 J
(c) 0.6627 * 100% / 1.0443 = 63.458%
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