41.m 417m 24N 10m s an electromagnetie wave ravels through free space (vacwom),
ID: 2037266 • Letter: 4
Question
41.m 417m 24N 10m s an electromagnetie wave ravels through free space (vacwom), s speed cn a. increasing its frequency b, increasing its energy only e increasing both its energy and momentum d. None of the above will increase its speed. be increased by 10. How large should a wall-mounted mirror be to view the upper half of one's height, a. c. h/4 d. The answer is not given. 11. A light ray in air is incident on an air-to-glass boundary at an angle of 30.0 to the normal and is refracted in the glass at an angle of 21.0° with the normal. Find the index of refraction of the glass. You may take the index of refraction of air to be 1.00. a. 2.13 b. 1.74 c. 1.23 d. 140 12. An bject and a screen are separated by 20.00 cm. A convex lens is placed between them n from the object. In this position it causes a sharp image of the object to form on the 5.00 c screen. What is the focal length of the lens? a. 15.0 cm b. 5.00 cm c. 3.75 cm d. 2.00 cmExplanation / Answer
10. Suppose the Total height is h
Mirror view the upper part bt image of upper part is shown half in the mirror
L = h /4
11. Use snell's law,
ni * sin thethai = nr * sin thetha r
1.00 * sin 30° = nr * sin 21°
0.5 = nr * 0.358
nr = 1.40
12. Total distance = 20
P = 5cm ( distance between lens and object)
Q = 15 cm ( distance between lens and screen)
1/f = (1/p) + (1/q)
1/f = (1/5) + (1/15)
1/f = 4/15
F = 3.75cm
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