Secure https://session.masteringphysics.com/myctfitemView?offset next&assignment

Question

Secure https://session.masteringphysics.com/myctfitemView?offset next&assignmentProblemID-92578470; Constants Part A A 720-kg boulder is raised from a quarry 147 m deep by a long uniform chain having a mass of 600 kg. This chain is of uniform strength, but at any point it can support a maximum tension no greater than 2.90 times ts weight without breaking. What is the maximum acceleration the boulder can have and still get out of the quarry? Submit Request Answer Part B How long does it take to be lifted out at maximum acceleration if it started from rest? ??? t- Submit st Answer Provide Feedback Next>

Explanation / Answer

mass of the chain per unit length = 600/147 kg/m = 4.08 kg/m

at any point x from the bottom of the chain.

mass of the chain hanging down = 4.08x

Tension at that poin T = 2.9*4.08x*g ( 2.9 times its mass) - max tension

let a be the acceleration

at a point x, the force acting on are

Tension T = 11.83xg upward.

Total weight hanging = 720g + 4.08xg

equation of motion

ma = T-(mg+4.08xg)

720a = 11.83xg - 720g - 4.08xg

= 419.25g ( max value of x=147m)

a = 0.58g , max acceleration.

distance s = 147 m ;

a = 0.58g = 5.68 m/s2

time of travel t = sqrt(2s/a) = sqrt(2*147/5.68) = 7.19 s

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.