021 (part 1 of 4) 10.0 points A 56 mH inductor, a 19.8 ? resistor, and a 4.7 V b

Question

021 (part 1 of 4) 10.0 points A 56 mH inductor, a 19.8 ? resistor, and a 4.7 V battery are connected in series. The switch is closed at t = 0. Find the voltage drop across the resistor at Answer in units of V. 022 (part 2 of 4) 10.0 points Find the voltage drop across the resistor after one time constant has passed. Answer in units of V. 023 (part 3 of 4) 10.0 points Find the voltage drop across the inductor at Answer in units of V. 024 (part 4 of 4) 10.0 points Find the voltage drop across the inductor af- ter one time constant has elapsed. Answer in units of V

Explanation / Answer

Given,

L = 56 mH ; R = 19.8 Ohm ; V = 4.7 V

021)at t = 0, the drop across the resistor is 0

Vr = 0

022)time const = tau

We know that

Vl = Vb e^-t/Tau

t = tau ;

Vl = 4.7 x e^-1 = 1.73 V

Vr = 4.7 - 1.73 = 2.97 V

Hence, Vr = 2.97 V

023)At t = 0s,Vl = Vb

Vl = 4.7 V

Related Questions

Navigate

• Browse (All)
• Browse
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.