Problem 20(4.00 points) A Hea+ ion is moving towards a proton (p) as shown in th
ID: 2036322 • Letter: P
Question
Problem 20(4.00 points) A Hea+ ion is moving towards a proton (p) as shown in the figure. The position of the proton is fixed. The dashed circles represent the equipotential surfaces around the proton and the electric potentials for each surface are shown in the figure.I the electric potential at that point is essentially equal to zero. The initial kinetic energy of the Hea* ion is 20 eV. Which of the following correctly describes the motion of the He2+ ion: (Note: charge for Heior +3.2x1049 C; charge of proton-+ 1.6×1019 C; 1 eV 1.6 x1019 J) 10 V 20 V : A He2 A) It will stop at point A and it will be bounced back B) It will stop at point B and it will be bounced back C) It will stop at point C and it will be bounced back- D) It will not stop until it touches the proton E) Insufficient information to determine at which point the He ion will stop.Explanation / Answer
Correct Ans is:
(A)It will stop at point A and will be bounced back.
explanation:
KEi = 20 eV ; this will get cons=verted to KE and the maximum energy required as seen in the figure is 40eV.
V = qV/q = 20eV/2e = 10 V
so it will go back from point A itself.
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