B, D 2 2 Figure 20.26 10 pt| Problem 20.4 The plane of a square loop of wire wit

Question

B, D 2 2 Figure 20.26 10 pt| Problem 20.4 The plane of a square loop of wire with edge length of 6.00cm is perpendicular to a 0.014T magnetic field (see the figure a)). What is the average emf between the points E1 and E2 when the corner D is quickly folded about the diagonal AC so as to lie on top of B (see the figure (b)) if it takes 0.180s to make the (in V) fold! 8. AO 1.43 x 10-4 BO 1.79 x 104 CO 2.24 x 10-4 DO 2.80x10-4 EO 3.50 x 10-4 FO 4.38x 10-4 GO 5.47 x 10-4 HO 6.84 x 10-4 IO 8.54 x 10-4 JO 1.07 x 103

Explanation / Answer

delta A = -0.06 * 0.06 = -0.0036 m2

emf = - delta(BA) / dt

= -B * delta A / delta t

= -0.014 * -0.0036 / 0.18

average emf = 2.80 * 10-4 V [option D]

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.