PLEASE SEE WHAT I WROTE IN BLUE. NOT just solve the problem with the answer I al

Question

PLEASE SEE WHAT I WROTE IN BLUE. NOT just solve the problem with the answer I already gave you... (this is my 2nd time posting this). I would like to UNDERSTAND how to do it.

Apparently the correct answer is C (per my instructor). But I am confused about two things 1. Why is F just W+V and not (W+V)g? I know that the normal force counteracts gravity or whatever, but that shouldn't allow us to Pressure under a table leg A object with weight of W (in N) is resting on a table withdisregard it, should it? Also, K legs each having a contact surface S (m2) with the floor. The weight of the table is V (in N). The pressure P exerted |deformation) we DID by each of the legs on the floor is: in some other questions (related to stress& consider gravity for the force. What is different here? a) (W+V)/S b) W/S c) (W+V)/(KS) d) W/(KS) e) (W+V)g/S with g-9.81 m/s2 2.| The question asks for P exerted by each leg, not the sum of P of all legs. I understand multiplying KS for the denominator (area) but wouldn't that give us TOTAL surface area? So then wouldn't we be calculating force per total surface area? Shouldn't we have to divide by k again Physics 23iC 28 (or just do kA2 in the denominator) in order to get P (or force per area) PER table leg (rather than per area total)?

Explanation / Answer

pressure is equal under all legs. pressure = total force/ total area   

W and V given are not mass they are weight (in Newton). W and V are given as mass x gravity  

gravity is already multiplied to mass of the object.   

force on each leg = (W+V)/K   
pressure on each leg = force on each leg/ area of each leg  
= (W+V)/(KS)

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