is covered, the intensity of the central the intensity of the central maximsum i
ID: 2035919 • Letter: I
Question
is covered, the intensity of the central the intensity of the central maximsum is lo Ifone of the slits d lo/2 e lo 4 2. The figure below shows a cross-sectional view of a perfect cube of refractive index surrounded by air. The ray of light shown enters the cube (as shown) and leaves exactly at the lower right edge (as shown). What must be the angle of incidence 0 between the incident light ray and the normal to the top face of the cube in 1.50 the cube exactly at the center of the top face of order for this to occur? a the situation described is not possible when the refractive index of the cube is 1.50 b. 48.6° c 17.3 d. 36.6 e. 421?Explanation / Answer
Using snell's law:
n1*sin A1 = n2*sin A2
n1 = refractive insec of air = 1
n2 = refractive index of cube = 1.50
When light leaves the cube it's angle will be same as angle of refraction (A2)
Suppose cube's side is x
tan (A2) = (x/2)/x
A2 = arctan (1/2) = 26.56 deg
So
A1 = arcsin ((n2/n1)*sin A2)
A1 = arcsin (1.50*sin 26.56 deg)
A1 = 42.1 deg
Correct option is E.
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