Assume all temperatures to be exact, and neglect significant figures for small c

Question

Assume all temperatures to be exact, and neglect significant figures for small changes in dimension.
During open-heart surgery it is common to cool the patient's body down to slow body processes and gain an extra margin of safety. A drop of 9 ?C is typical in these types of operations.

Part A

If a patient's normal body temperature is 98.1 ?F, what is her final temperature in both Celsius?

36.7

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Part B

What is her final temperature in Fahrenheit?

Assume all temperatures to be exact, and neglect significant figures for small changes in dimension.
During open-heart surgery it is common to cool the patient's body down to slow body processes and gain an extra margin of safety. A drop of 9 ?C is typical in these types of operations.

Part A

If a patient's normal body temperature is 98.1 ?F, what is her final temperature in both Celsius?

TC=

36.7

?C

SubmitPrevious AnswersRequest Answer

Incorrect; Try Again; 7 attempts remaining

Part B

What is her final temperature in Fahrenheit?

TF=

Explanation / Answer

Part A:

Relation between F and C is given by:

C = (5/9)*(F - 32)

Given that normal body temperature is 98.1 F, then

Normal body temperature in Celsius will be

C = (5/9)*(98.1 - 32) = 36.7 C

Final body temperature in Celsius = 36.7 - 9 = 27.7 C

Part B

C = (5/9)*(F - 32)

F = 9C/5 + 32

When C = 27.7, then

F = 9*27.7/5 + 32 = 81.7 F

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