A racquet ball with mass m-0.252 kg is moving toward the wall at v- 18.3 m/s and

Question

A racquet ball with mass m-0.252 kg is moving toward the wall at v- 18.3 m/s and at an angle of 8 25" with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. The ball is in contact with the wall for t 0.06s 1) What is the magnitude of the initial momenturn of the racquet ball? 4.61 kg-m/s Submit 2) What is the magnitude of the change in momentum of the racquet ball? 9.22 kg-m/s Submit 3) What is the magnitude of the average force the wall exerts on the racquet bal? 153.72 N Submt 4) Now the racquet ball is moving straight toward the wall at a velocity of v, 18.3 m/s. The ball makes an inelastic collision with the solid wall and leaves the wall in the opposite direction at -11.2 m/s. The ball exerts the same average force on the ball as before What is the magnitude of the change in momentum of the racquet ball? kg-m/s Submit 5) What is the time the ball is in contact with the wall? s Submit 6) What s the change in kinetic energy of the racquet ball?

Explanation / Answer

here,

mass of ball , m = 0.252 kg

initial speed , u = 18.3 m/s

theta = 25 degree

t = 0.06 s

a)

the magnitude of initial momentum of ball , Pi = m * u = 4.61 kg.m/s

b)

the magnitude of change in momentum of the ball , dP = m * (u * cos(theta) - ( u * cos(theta)) )

dP = 0.252 * 2 * 18.3 * cos(25) kg.m/s

dP = 8.36 kg.m/s

c)

the magnitude of the average force on wall , F = dP /t

F = 139.3 N

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