Two springs are connected in series as illustrated. How does the total spring co

Question

Two springs are connected in series as illustrated. How does the total spring constant compare to the individual spring constants?

The total spring content is lower than the lower spring constant ______
The total spring content is higher than the higher spring constant ______
The total spring content is equal to the sum of the two spring constants ______
Justify your answer.

3. Two springs are connected in series as illustrated. How does the total spring constant compare to the individual spring constants? k1 and x1 k2 and x2 Ftot er spring constant _ The total spring content is higher than the higher spring constant The total spring content is equal to the sum of the two spring constant:s Justify your answer.

Explanation / Answer

Ans:-

For spring 1 Hook’s law

F = k1x1

x1= deformation of spring

k1- spring const

Similarly for second spring

F= k2x2

Total deformation of the system

x1 +x2 = F/k1 +F/k2

x1+x2 = F` (1/k1 +1/K2)

Rewriting and comparing with Hook’s law we get

k = (1/k1 +1/k2)^-1

k=(1/k1)^-1 +( 1/k2)^-1

k = k1 + k2

The total spring content is equal to the sum of the spring constants

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