o 2.75/7 points T Previous Answers SerPSE9 33 AE Example 33.4 Analyzing a Series

Question

o 2.75/7 points T Previous Answers SerPSE9 33 AE Example 33.4 Analyzing a Series RLCCircuit A series RLC circuit has R 450 ?, L-: 1.20 Hr C 3 ?F·It is connected to an AC source with f's 60.0 Hz and ??,ar-150 V. ?????+??.-4.-MC SOLVE IT (A) Determine the inductive reactance, the capacitive reactance, and the impedance of the circuit. Conceptualize The circuit of interest in this example is shown in the figure. The current in the combination of the resistor, inductor, and capacitor oscillates at a particular phase angle with respect to the applied voltage. A series circuit consisting of a resistor. an inductor, and a capacitor ronnected to an AC source. Categorize The circuit is a simple series RLC circuit, so we can use the approach discussed in this section. Analyze Find the angular frequency:

Explanation / Answer

initially,

R = 450 ohm

xL = 2 pi f L = 2 x pi x 60 x 1.20 = 452.4 ohm

Xc = 1/(2 pi f C) = 884.2 Ohm

Z = sqrt[ R^2 + (XL - XC)^2 ] = 624 ohm

now f = 85 Hz

so XL = 641 ohm

Xc = 624 ohm

Z^2 = R^2 + (XL - Xc)^2

624^2 = R^2 + (641 - 624)^2

R = 624 ohm ....Ans

(B) phi = tan^-1 [ XL - XC / R]

= tan^-1 [ (641 - 624)/624]

= 1.6 deg

(C) I = V / Z = 0.24 A

VR = I R = 150 Volt

VL = I XL = 154 Volt

Vc = I Xc = 150 Volt

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.