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HW 8 Begin Date: 3/23/2018 12:00:00 PM -- Due Date: 4/2/2018 11:59:00 PM End Dat

ID: 2034652 • Letter: H

Question

HW 8 Begin Date: 3/23/2018 12:00:00 PM -- Due Date: 4/2/2018 11:59:00 PM End Date: 4/2/2018 11:59:00 PM (6%) Problem 12. A beam, uniform in mass, M-67 kg and length L-28 m, hangs by a cable supported at point B, and rotates without friction around point A. On the end far of the beam, an object of mass m - 2 kg is hanging. The beam is making an angle of ?-25° at pointA with respect to the + x-axis. The cable makes an angle ? -29° with respect to the-x-axis at B. Assume ?-? + ?. Assume u/ + 9. Otheexpertta.com 14% Part (a) Select the correct free body diagram In the figure the tension is T, horizontal and vertical components of the support force are Sx and Sy, FB is the weight of the beam, and Fm is the weight of the mass. i4% Part (b) what is the lever arm for the weight of the beam, IB, about the point A? i 4% Part (c) What is the lever arm for the the weight of the mass, 1m? 14% Part (d) Write an expression for the magnitude of the torque about point A created by the tension ?71n terms of the given variables and trigonometric functions 14% Part (e) What is the magnitude of the tension in the cable in Newtons? -? 14% Part (f) What is the horizontal force sr the wall exerts on the beam at point A in terms of the tension T?

Explanation / Answer

(E) balancing moment about point A,

M = (67 x 9.8 x 14 x cos25) + (2 x 9.8 x 28 x cos25) - (28 x T x sin(29 + 25)) = 0

8331.14 + 497.38 - 22.65 T = 0

T = 390 N

(f) in horizontal,

Fx_net = Sx - T cos29 = 0

Sx = 341 N