Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

ttps://edugen.wileyplus.com/edugen/student)/mainfr.uni Text Search . IEEE Compi

ID: 2034188 • Letter: T

Question

ttps://edugen.wileyplus.com/edugen/student)/mainfr.uni Text Search . IEEE Compi D Net Neutrality vs Net M T D Weather 0 RADAR 2 Peter 1 ? 2 Peter 1:1 I Hep I Contact s I Leg O S Halliday, Fundamentals of physics, loe PHYSICS FOR SCIE NCE AND ENGINEERING (PHYS 2110/ 2120 ctice Assignment Gradebook ORION Downloadable eTextbook nment FULL SCREEN PRINTER VERSIONBACK RACK Chapter 11, Problem 058 A horlzontal platform in the shape of a circular disk rotates on a frictionless bearing about a vertical axde through the center of the disk. The platform has a radius of 2.59 m and a rotational inertia of 227 kg-m2 about the axis of rotation. A 59.4 kg student walks slowly from the rim of the platform toward the center. If the angular speed of the system is 1.57 rad/s when the student starts at the rim, what is the angular speed when she is 0.975 m from the center? Number ( the tolerance is +/-6% Click if you would like to Show Work for this question: Units oen Show Work SHOW HINT By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor. Question Attempts: 0 of 3 used SAE OR LATER SUIMIT ANSWER All Rights Version 4.24.5.1

Explanation / Answer


intial rotational inertia

Ii = Idsk + I student

Idisk = 227 kg.m^2

I student = Mr^2 = 59.4* 02.59^2

final rotational inertia  

If = Idisk + I student

Istudent = 59.4* 0.975^2

from the law of Conservation of angualr momentum

I1 W1 = I2 W2

W2 = (227 + 59.4* 02.59^2 )* 1.57/(227 + 59.4* 0.975^2 )

W2 = 3.46 rad/s