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ssee Tech- Tenness Sapling Learning login pageTN eCampus PHYS 21 X+ ? ? www sapinglearningcorn ibiscrns/moo/ibis/ie php?id-5014172&proceed-1; e, select t then x, and drag to the Favorites Bar folder. Or import from another browser. Import favorites g Learning 3/30/2018 10:55 PM 4 Time Remaining: 57 MA3S Gradebook Question 4 of 6 Sapling Learning Sean Cordry at Waer Consider the circuit shown. The table below has the values of the componenets R2 V 700 v R1 227 0 R2 334 ? AV Answer the three questions below, using three significant figures Part A: Determine the current (k) flowing through the resistor R Number mA (Note the units for current) Part B: Determine the voltage drop (AV) across the resistor Rs Number Part C: How much power (Pre) is supplied by the EMF source (the battery) tn the Save And Exit O Prevo-o Next o e ere to search

Explanation / Answer

Remember:
For series combination
Req = R1 + R2 + R3 +...............
for parallel combination
1/Req = 1/R1 + 1/R2 + 1/R3 + ............
for 2 resistors in parallel it will be
Req = R1*R2/(R1+R2)
Using this Information:

Part A

R1 and R2 are in circuit, So

Req = R1 + R2

Req = 227 + 334 = 561 ohm

Using Ohm's law:

V = i*Req

i = V/Req = 7/561 = 0.01248 Amp

Now remember in resistors parallel combination voltage distribution in each part will be same and in series combination current distribution in each resistor will be same. So

Current in R1 = Total current

i1 = 0.01248 Amp = 12.48 mA

Part B

V1 = i1*R1

V1 = 12.48*10^-3*227

V1 = 2.83 V

Part C

Power is given by:

P = V^2/Req

P = 7^2/561 = 0.08734 W

P = 87.34 mW

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