12. The figure below illustrates a mass spectrometer. Positive ions (q-1.6x 10.1
ID: 2033173 • Letter: 1
Question
12. The figure below illustrates a mass spectrometer. Positive ions (q-1.6x 10.19 c) leave the ion source and enter a velocity selector composed of two parallel metal plates 1 cm apart with a magnet field in the green region. The electric field between the plates is 2500 V/m adjusted until the ions go straight across. If the desired speed is 7 x 104 m/what is the strength of the magnetic field in v the first (green) region? A. 0.035T B.0.5T C.1T D. 1.5T E. 2T 13. If the magnetic field, B', in the blue area is 0.5 T and the radius of the semi- circular orbit is 25 centimeters, what is the mass of the ion? A.1.16 x 1026 kg B.2.9 x 1024kg C2.9 x 1028kg E14 kg 14. The red charge in the figure is negative, the green is positive, and the blue is also negative. The magnetic field is into the page. What is the direction of the force on the green charge? x x X X X X X X X Green a. Points into the page b. points out of the page e. Points up d. Points down e. points left 15. What is the direction of the force on the red charge? a. Points into the page b. points out of the page c. Points up e. Points left d. points right 16. What is the magnitude of the current in a loop containing a 2 ohm resistor rolling on two condueting rods with a siding of 1 m traveling at 5 m/s perpendicular to a 5.0 x a10 T magnetie field? .4 -5 -4 .2Explanation / Answer
(12) In velocity filter the
electric force = magnetic force
qE = BqV
where E is electric field , V is velocity of ion , B is magnetic field
B = E/V = 2500 /(7*104)
B = 0.035 T
hence the correct option will be A.
(13) In this case centripetal force must be provided by the magnetic force , therefore
BqV = m(V2)/r
wherer r is the radius of path
m = Bqr / V
m = 0.5*1.6*10-19*(2.5*10-2) /(7*104)
m = 2.9*10-24 kg
Hence the correct option would be B.
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