2. A 20 g ball of clay traveling east at 3.0 m/s collides with a 30 g ball of cl

Question

2. A 20 g ball of clay traveling east at 3.0 m/s collides with a 30 g ball of clay traveling north at 2.0 m/s. The balls stick together after the collision. What are the speed and direction of the resulting 50 g ball of clay? Sketch the before and after state of the system. 3. A 140 g baseball is moving horizontally to the right at 35 m/s when it is hit by the bat The ball flies off to the left at 55 m/s, at an angle of 25° above horizontal. What are the magnitude and direction of the impulse that bat delivers to the ball? Sketch the collision below

Explanation / Answer

2) m1v1 + m2v2 = (m1+m2)v

in x-direction,

0.02*3 + 0 = 0.05*v

vx = 1.2 m/s

in y- direction,

0 + 0.03*2 = 0.05*v

vy = 1.2 m/s

so, v = sqrt (v2x + v2y )

v = 1.697 m/s

theta = tan-1 1

theta = 45 degree

3) In y-direction,

vy = 55*sin25 = 23.24 m/s

In x-direction

vx = 35 + 55*cos25

vx = 84.85 m/s

v = 87.98 m/s

impulse = change in momentum = mv = 0.14*87.98 = 12.32 kgm/s

theta = tan-1 ( 0.2739)

theta = 15.32 degree

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