-14 points SerPSE9 9 P 051 W My Notes Ask Yo A 2.04-kg particle has a velocity (

Question

-14 points SerPSE9 9 P 051 W My Notes Ask Yo A 2.04-kg particle has a velocity (2.06 ?-3.01 j) m/s, and a 3.10-kg partide has a velocity (109 Í + 5.98 j) m/s. (a) Find the velocity of the center of mass. j m/s (b) Find the total momentum of the system j) kg m/s Need Help? Lerdil Lenn. O 415 points My Notes Ask You 1 Previous Answers SerPSE9 9 P054 The vector position of a 3.-40 g particle moving in the xy plane varies in time according to r, (3i+3))+ 2j2 wh is in seconds and ? is in centimeters. At the same time, the vector position of a 6.00 g particle varies as (a) Determine the vector position of the center of mass at t 2.60. am-l-3.89t-2.25] v (b) Determine the linear momentum of the system at t-2.60 p-| (-52.21+9.56) |V g. crn/s (c) Determine the velocity of the center of mass at t-2.60. Vcm-5.55i 1.017jcm/s (d) Determine the acceleration of the center of mass at t-2.60. (e) Determine the net force exerted on the two-partidle system at t 2.60. /28/2018

Explanation / Answer

a) VCM = (2.04 x 2.06 + 3.10 x1.09) / ( 2.04 + 3.10) i + ( 2.04 x - 3.01 + 3.10 x 5.98 ) j / (2.04 + 3.10) = ( 7.5814/ 5.14) i + (12.3976 / 5.14) j = 1.47 i + 2.41 j

b) Total momnetum= (2.04 x 2.06 + 3.10 x1.09) i + (2.04 x - 3.01 + 3.10 x 5.98 ) j= 7.58? i + 12.4 j

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