9. A lighted candle is placed 36.0 cm in front of a diverging lens. The light pa

Question

9. A lighted candle is placed 36.0 cm in front of a diverging lens. The light passes through the diverging lens and on to a converging lens of focal length 10.0 cm that is 5.00 cm from the diverging lens. The final image is real, inverted, and 43.0 cm beyond the converging lens. Find the focal length of the diverging lens cm 10. A converging lens (f .0 cm) is located 27.0 cm to the left of a diverging lens (f2 5.46 cm). A postage stamp is placed 38.1 cm to the left of the converging lens. Locate the inal image of the stamp relative to the diverging lens. cm

Explanation / Answer

10.

first find image distance for converging lens

f = 11.0 cm

u = 38.1 cm

1/f = 1/u + 1/v

v = f*u/(u - f) = 11.0*38.1/(38.1 - 11.0) = 15.46 cm

Now this image will work like object for diverging lens, So now

f1 = -5.46 cm

u1 = 27.0 - 15.46 = 11.54 cm

1/f1 = 1/u1 + 1/v1

v1 = f1*u1/(u1 - f1)

v1 = 11.54*(-5.46)/(11.54 - (-5.46))

v1 = -3.71 cm (-ve sign means image is to the left of diverging lens)

Please Upvote. Let me know if you have any doubt.

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