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/3 pointsHRW10 13.P.040 A projectile is shot directly away from Earth\'s surface

ID: 2032688 • Letter: #

Question

/3 pointsHRW10 13.P.040 A projectile is shot directly away from Earth's surface. Neglect the rotation of Earth (a) As a multiple of Earth's radius RE, what is the radial distance a projectile reaches if its initial speed is 0.480 of the escape speed from Earth? (b) As a multiple of Earth's radius RE, what is the radial distance a projectile reaches if its initial d to escape Earth? x RE (c) What is the least initial Earth? mechanical energy required at launch if the projectile is to escape Additional Materials 9.-/1 pointsHRW10 13.P.048 The mean distance of an asteroid from the Sun is 3.20 times that of Earth from the Sun. From Kepler's law of periods, calculate the number of years requir Sun. ed for the asteroid to make one revolution about the yr Additional Materials 10,-/2 pointsHRW10 13.P.072 A typical neutron star may have a mass equal to that of the Sun but a radius of only 20 km. (a) What is the gravitational acceleration at the surface of such a star? (Enter the magnitude.) m/s2 (b) How fast would an object be moving if it ell frfom rest through a distance of 1.2 m on such a star? (Assume the star does not rotate.) m/s Section 13.1 18440704 1/6

Explanation / Answer

10.

gravitational acceleration is given by:

g = GM/R^2

M = mass of sun = 1.989*10^30 kg

R = 20 km = 20000 m

So,

g = 6.67*10^-11*1.989*10^30/20000^2

g = 3.32*10^11 m/sec^2

Part B

V^2 = U^2 + 2*a*d

V = sqrt (0^2 + 2*3.32*10^11*1.2)

V = 8.93*10^5 m/sec