328/2018 PHYS 201 Assignment Thirteen-Chapter Fifteen 6. -/1 pointsHRW10 15.P.04
ID: 2032640 • Letter: 3
Question
328/2018 PHYS 201 Assignment Thirteen-Chapter Fifteen 6. -/1 pointsHRW10 15.P.040. A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance x from the 50 cm mark. The period of oscillation is observed to be 5.0 s. Find the distance x. Additional Materials 7. -/1 pointsHRW10 15.P.058. In the figure below, a damped simple harmonic oscillator has mass m = 240 g, k-95 N/m, and b-65 g/s. Assume all other components have negligible mass. What is the ratio of the amplitude of the damped oscillations to the initial amplitude at the end of 20 cycles? Adamped/Ainitial xRigid support Springiness, k Mass m Vane Damping,b Additional MaterialsExplanation / Answer
6)
equivalent length
Leq = I / mx
where I is the moment of inertia about the pivot
and m is the mass
and x is the distance from the pivot to the center of mass
By the parallel axis theorem,
I = mL²/12 + mx², so
Leq = (mL²/12 + mx²) / md = L²/12x + x
period T = 2??(Leq / g) ? square everything
T² = 4?²(L²/12x + x) / g
gT² / 4?² = L²/12x + x ? plug in g and T and drop units for ease (x is in meters):
9.8*(5)² / 4?² = 1/12d + x
6.21 = 1/12x + x ? multiply by x
6.21x = 1/12 + x²
0 = x² - 6.21x + 1/12
This quadratic has roots at
x = 0.01345 m ? solution
(and x = 6.2 m ? greater than 1 m; disregard)
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