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ulse the follotwing U-tube setup to answer questions 6 through 8 2.0 M sucrose E

ID: 203262 • Letter: U

Question

ulse the follotwing U-tube setup to answer questions 6 through 8 2.0 M sucrose E 1.0 M glucose 1.0 M sucrose 2.0 M glucose selectively permeable membrane The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is filled with a solution of 2.0 M sucrose and 1.0 M glucose. Side B is filled with 1.0 M sucrose and 2.0 M glucose. 6. Initially, the solution in side A, with respect to that in side B, a. has a lower solute concentration. b. has a higher solute concentration. c. has an equal solute concentration. d. is higher in the tube. 7. During the period before equilibrium is reached, which molecule(s) will show net movement through the membrane? a. water b. glucose c. water and sucrose d. water and glucose 8. After the system reaches equilibrium, what changes can be observed? a. The water level is higher in side A than in side B. b. The water level is higher in side B than in side A. c. The molarity of glucose is higher in side A than in side B. d. Both a and c have occurred.

Explanation / Answer

6. Initially the solution in side A, with respect to solution in side B,

7. During the period when equilibrium is reached, which molecules will show net movement through the membrane?

Explanation: As stated the sucrose molecules cannot cross the permeable membrane, only water and glucose molecule will pass through.

8. After the system reaches equilibrium, what changes can be observed?

Explanation: Side b will become hypotonic solution hence water will rush through the semi permable membrane and water level will be higher inside A than B.