12. 0/4 points | Previous Answers SerPSE9 7 P036. In an electron microscope, the
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12. 0/4 points | Previous Answers SerPSE9 7 P036. In an electron microscope, there is an electron gun that contains two charged metallic plates 2.50 cm apart. An electric force accelerates each electron in the beam from rest to 9.70% of the speed of light over this distance. (Ignore the effects of relativity in your calculations.) My Notes Ask Your Teacher (a) Determine the kinetic energy of the electron as it leaves the electron gun. Electrons carry this energy to a phosphorescent viewing screen where the microscope's image is formed, making it glow. 2408.06 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. J (b) For an electron passing between the plates in the electron gun, determine the magnitude of the constant electric force acting on the electron 1.544E-15 | Your response is off by a multiple of ten. N (c) Determine the acceleration of the electron. m/s2 (d) Determine the time interval the electron spends between the plates.Explanation / Answer
a) KE = ½ mv2
= 0.5*(9.11*10^-31)*(0.097*3.0*10^8)^2 = 3.86*10^-16 J
b) time, 't' required for acceleration = 0.025/[0.5*0.097*3.0*10^8], where [0.5*0.097*3.0*10^8] m/s is average velocity, or
t = 1.718*10^-9 s
acceleration, a = [0.097*3.0*10^8]/[1.718*10^-9] = 1.69*10^16 m/s^2
Force = ma = (9.11*10^-31)*( 1.65*10^16) = 1.54*10^-14 N
c) a = 1.69*10^16 m/s^2
d) t = 1.718*10^-9 s
[c) and d) were already calculated.]
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