Using Faraday\'s Law, calculate the induced emf around the loop in the figure th

Question

Using Faraday's Law, calculate the induced emf around the loop in the figure that is caused by the changing flux. Assign clockwise to be the positive direction for emf.
The emf around the loop causes a current to flow. How large is that current? (Again, use a positive value for clockwise direction.)

Remember F=ma: since v is constant, a=0, so it must be true that the net force on the rod is zero. The pulling force is compensating the force on the rod due to the current through it and the magnetic field.

From your previous results, what must be the electrical resistance of the loop? (The resistance of the rails is negligible compared to the resistance of the rod, so the resistance of the loop is constant.)
Tries 0/5 The rate at which the external force does mechanical work must be equal to the rate at which energy is dissipated in the circuit. What is that rate of energy dissipation (power dissipated)? ?????

Explanation / Answer

a) Induced emf = B d v

= 0.700 * 0.26 * 5.90 = -1.07 V

b) F = I d B

I = F / d B

= 4.8 / (0.26 * 0.70) = 26.37 A

direction of current will be in clockwise direction

c) Resistance R = V / I

= 1.07 / 26.37 = 0.0405 ohms

d) Power P = I V

= 1.07 * 26.37 = 28.2 W

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