6. Two pieces of clay are thrown horizontally at each other. One piece of clay h
ID: 2031903 • Letter: 6
Question
6. Two pieces of clay are thrown horizontally at each other. One piece of clay has a mass of 200g, and moves with a speed of 2.5m/s. The other piece of clay has a mass of 350g, and moves with a speed of 1.2m/s. How fast do the lumps of clay move after the collision if they stick together? 30° measured from the vertical axis. When it reaches 0° (ie. when it's pointing straight down), it hits a 1.2kg block of wood. How fast does the block of wood move after being hit by the pendulum? 8. A pendulum 0.8m long, with a 250g mass attached at the end, is dropped from an angle of 7. Suppose the wheel of a car has a radius of 17cm and a mass of 15kg. The axle passing through each wheel produces about 5Nm of torque due to friction. If the engine of a car produces 200Nm of torque, split evenly between its four wheels, what is the linear acceleration of the car assuming the wheels roll without slipping? Treat each wheel as a solid cylinder. 8. A hollow cylinder, with a mass of 1.3kg and a radius of 5cm, is released from rest at a height of 0.7m on a frictionless incline. If it rolls without slipping, what will its translational speed be at the bottom of the incline? 9. Imagine a 1.6kg mass hanging from a rope wound around a 2.5kg, solid cylinder with a 15em radius, as shown in the figure above. If the block was released from rest and allowed to drop 1m, how fast would the cylinder be rotating? Note that the cylinder is fixed such that it rotates about an axis through its center. Before After 10. A 1.5kg cylinder, with a radius of 20cm, is rotating at a speed of 45 rad/s about an axis through its center. Suddenly, a smaller cylinder, with a radius of 7em and a mass of 500g, is dropped on top of the larger cylinder such that it also rotates about its center, as shown in the figure. At what speed do the two cylinders rotate?Explanation / Answer
6)
Let v be the final velocity.
Use conservation of momentum:
Initial momentum = final momentum
m1v1 + m2v2 = (m1+m2) v
(200*2.5) + (350*1.2) = (200+350)v
=> v = [(200*2.5) + (350*1.2)]/(200+350)
= 1.67 m/s
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.