6. -/6 points SerPSE9 8.P016.soin. My Notes Ask Your Teacher A 34.5 kg box initi

Question

6. -/6 points SerPSE9 8.P016.soin. My Notes Ask Your Teacher A 34.5 kg box initially at rest is pushed 5.65 m along a rough, horizontal floor with a constant applied horizontal force of 140 N. If the coefficient of friction between box and floor is 0.300, find the following. (a) the work done by the applied force (b) the increase in internal energy in the box-floor system due to friction (c) the work done by the normal force (d) the work done by the gravitational force (e) the change in kinetic energy of the box (f) the final speed of the box m/s 7. 2/2 points | Previous Answers SerPSE9 8.P017 My Notes Ask Your Teacher O

Explanation / Answer

a)

Work done by the applied force is

W=Fd =140*5.65 =791 J

b)

The Increase in internal energy

dU=umgd =0.3*34.5*9.81*5.65 =573.66 J

c)

Work done by normal force

WN=0 J

d)Work done by gravitational force

W=0 J

e)

Change in Kinetic energy of the box

dK=791-573.66 =217.34 J

f)

(1/2)*34.5*V2=217.34

V=3.55 m/s

Related Questions

Navigate

• Browse (All)
• Browse 6
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.