chapter 28, Problem 010 ?proton traves through unifonm magnetic and electric fie

Question

chapter 28, Problem 010 ?proton traves through unifonm magnetic and electric fields. The magnetic field s in the negative direct on and has a magnitude of 3.13 mT At one instant the velocity of the proton is in the posit ve y direction and has a magnitude o 1720 m s. At that instant, hat is the magnitude of the net force acting on the proton If the ellectric field is (a) in the positve z direction and has a magnitude of 4.13 /m, (b) in the negatve z direction and has a magnitude of 4.13 V/m, and (c) in the positive x direction and has a magnitude of 4.13 m? (a) Number (b) Numbe (c) Numbar Click if you Units Units Units orko this question: f Show Mor

Explanation / Answer

a) f = q(E+v*B)

F = 1.6*10^-19(4.13k+3.13*10^-3*1720k) = 1.52*10^-18 k N

b) f = 1.6*10^-19(-4.13k+3.13*10^-3*1720k) =2.0*10^-19 k N

c) f = 1.6*10^-19(4.13i+3.13*10^-3*1720k) = (6.608i+8.6k)*10^-19 N

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