Window Help 23% Mon 9:15 PM AlerVaraksa PHY 153 PS9 The Students NSU Suomit Answ

Question

Window Help 23% Mon 9:15 PM AlerVaraksa PHY 153 PS9 The Students NSU Suomit Answer Pracice Another Version Practice Another Version .-H18 points os 6 232WA.004. My Note A rectangular box is placed in a region where there is a uniform magnetic field of magnitude 0.0240 T directed to the right. In the diagram, the green arrows. Here cg 36.0 cm, ab 10.0 cm, and bc 12.0 cm. Determine the magnetic flux, including the sign, through each of the six faces of the box. ?.bed- Wb Wb Wb Wb Additional Materials LReading

Explanation / Answer

Magnetic flux is given by:

phi = B.A = B*A*cos theta

the sides which are parallel to the field, for them

theta = 90 deg

cos 90 deg = 0

So,

phi = B*A*cos 90 deg = 0

These sides are

abcd, efgh, cdgh, & abef

So for (i), (iii), (iv) & (vi), phi = 0

for part ii (bcgf)

phi = B*A*cos theta

theta = 0 deg

phi = 0.0240*0.12*0.36*cos 0 deg

phi = 1.04*10^-3 Wb

for part iv (adhe)

phi = B*A*cos theta

theta = 180 deg

phi = 0.0240*0.12*0.36*cos 180 deg

phi = -1.04*10^-3 Wb

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