Prnt h Caluator -d Periodic Table Question 2 of 2 Sapling Learning Mapo case all

Question

Prnt h Caluator -d Periodic Table Question 2 of 2 Sapling Learning Mapo case allele pumpkin, aabbccddee, weighs 20 lbs. Each capitalized allele additively affects the final phenotype by either capitalized allele is listed in the table below. or subtracting weight from the base pumpkin size. The effect of a single What would the potential size range be for pumpkin offs with genotype AaBBCcddEE and a parent with genotype AABbocDDEe? uced from the cross between a parent Allele Effect Number A +6Largest pumpkin 31 lbs .2 -3 Number Smallest pumpkin- 21 lbs There is a hint available! View the hint by clicking on the bottom divider bar. Click on the divider bar again to hide the hint Hint O Previous Give Up & View Soution Check Answer Next el Exit

Explanation / Answer

Parent aaBBCcddEE (lets say parent 1) will produce gametes a, B, C/c, d, E

Parent AABbccDDEe (lets say parent 2) will produce gametes A, B/b, c, D, E/e

We know that A, D, and E will increase mass whereas B and C will decrease mass.

Hence, the heaviest pumpkin will be obtained when parent 1 will produce gamete aBcdE and parent 2 will produce gamete AbcDE. The progeny will be AaBBccDdEE, weight = 20+(+6-2-2+3+4+4) = 33 lbs.

Similarly, the lightest pumpkin will be obtained when parent 1 will produce gamete aBCdE and parent 2 will produce gamete ABce. The progeny will be aaBbCCDdee, weight = 20+(-2-3-3+3) = 15 lbs.

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