the data table at resonance ne Ri using Z capacitor in the eircuit C the inducta
ID: 2030684 • Letter: T
Question
the data table at resonance ne Ri using Z capacitor in the eircuit C the inductance, L, for the resonant frequeney k. and the formula used, in the lab report. Show Work, Tip: At jHelc are intrinsic properties of the passive circuit components, they do not cha of R, L and C used in the circuit. Since R, L be shown in lab reporti they do not change with complete Data sht each frequency in Data Sheet L To calculate Zay, you needto complete Data Sheet 2 Part A first, from where you will know the va and R of the circuit. The values of L, C and R are independent At designated frequencies in the Data Table, calculate the impedanic of input frequency the values of C, L, R, Ri and f lot Impedance (Z) vs. frequency on the log-log paper using bon set of data pointsltss Zbeory (two plots on one sheet) use a smooth curve to conn Plot per using both Zmas and each set of data Here are few questions you would want to answer in your lab report by using the data obtained and the graph plotted: From the graph, determine At what frequency does Zmeas have its minimum value? At resonance describe the phase relationship of the voltage and current. Also at resonance describe the relationship between Inductive and Capacitive reactance. At resonance which components of the AC circuit contributes most to the total impedance of the circuit. If the circuit used in this experiment were to be adjusted for a resonant frequency of 3500Hz what value would the Inductor need to be set to?Explanation / Answer
From the given data
a. Zmean ( impedance) has minimum value at w = 1/sqrt(LC)
L = 0.0146 H
C = 0.3 uF
hence
w = 1/sqrt(0.0146*0.3*10^-6) = 15109.9471 rad/s
f = w/2pi = 2404.82277565836756 Hz
b. at resonance, the current and voltage are in phase and when voltage is maximum, the current is maxium too, and vice versa
c. during resonance, inductive reactance and capacitative reactance are equal in magnitude but, they are put of phase and hence cancel each other out
d. at resonance, only the resistance of the circuit contributes the most to the impedance of the circuit
e. for
f = 3500 Hz
w = 2*pi*f = 1/sqrt(LC)
C = 0.3 uF
hence
L = 0.006892597 H
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