answer all questions please «Oli 0 F.111-6:30 PM //www.flipitphysics.com 2 A sol

Question

answer all questions please

«Oli 0 F.111-6:30 PM //www.flipitphysics.com 2 A solld Insulating sphere of radlus a 3.7 cm is fixed at the origin of a co ordinate systeri as shown. The sphere s uniformly charged with a charge density p-181 uc/m3 concentric with the sphere is an uncharged spherical conducting shell of inner radius b 1.6 cm, and outer radius c = 13.6 cm. What ls E,P, thex-component of the electric field at point located a distance d 31 m frorri the origiri along the x axis as shown? Wt is ( he electrc potel at the inner surface of the conducting shel? Define the potentlal to be zero at Infinity. WhatIsVa), the electric potentlal at the outer surface of the insulating sphere? Define the potental to be zero at infirity. "what s Vc) V(a), the potentital differnece between the outer surface of the conductor and the outer surfaca of the Insulator? "A charge Q = ü.0722 C is now added to the shel. What is Via), the electric potential at the outer surface of the insulating sphere, nw? Defirne the potential to be zero at infirity Srcy Quntian Below Is sme apace to wrte notes on this problem.

Explanation / Answer

For the given data

insulating sphere, a = 3.7 cm

rho = -191 uC/m^3 uniformly charged

uncharged conducting shell

b = 11.6 cm

c = 13.6 cm

a. at d = 31 cm

Ex = k*rho*4*pi*a^3/3*d^2 = 8.98*10^9*(-191*10^-6)*4*pi*0.037^3/3*0.31^2

Ex =-3786.86739572 V/m

b. on the inner surfacce of conducting shell

potential Vb = k(rho*4*pi*a^3)/3*b

Vb = 8.98*10^9*-191*10^-6)*4*pi*0.037^3/3*0.116 = -3137.2237649 V

c. hence

Va = k*rho*4*pi*a^3/3*a = k*rho*4*pi*a^2/3 = -9835.6204521 V

d. Vc = k*rho*4*pi*a^3/3*b ( because electric field inside the conductor is 0)

hence

Vc = Vb

hence

Vc - Vb = 0 V

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