please finish all 3 of the related subsections and keep the steps neat so I can
ID: 2030532 • Letter: P
Question
please finish all 3 of the related subsections and keep the steps neat so I can understand what's going on. thank u so much for ur patience
is pressed against a spring of force constant 1.50 kN/m until the block compresses the spring 10.0 cm. The sp A 220-g block horizontal. Using energy considerations, determi ring rests at the bottom of a ramp inclined at 60.0° to the ne how far up the incline the block moves from its initial position before it stops under the following conditions. (a) if the ramp exerts no friction force on the block (b) if the coefficient of kinetic friction is 0.360 Im 8 8 P022.WI My n. com certof iction Det een t e blick of mass mi m2 5.00 kg when it has fallen a distance h 1.30 m? o 'g and the surface in e figure below s .-0.240. T e system starts from rest. what is the speed of the ball of ass m/s Type here to searchExplanation / Answer
total energy at the bottom = total energy on the inclin when the block stops instantaneously
(a)
initial energy Ei = (1/2)*k*x^2
final energy Ef = gravitational potential energy m*g*L*sintheta
Ef = Ei
m*g*L*sintheta = (1/2)*k*x^2
0.22*9.8*L*sin60 = (1/2)*1.5*10^3*0.1^2
L = 4.02 m
the block stops at a distance 4.02 m up the incline
(b)
initial energy Ei = (1/2)**x^2
final energy Ef = gravitational potential energy m*g*L*sintheta
friction force fk = uk*m*g*costheta
work done by friction Wf = fk*L*cos180 ( f and L are opposite)
work done by friction Wf = -uk*m*g*L*costheta
Ei + Wf = Ef
(1/2)*k*x^2 - uk*m*g*L*costheta = m*g*L*sintheta
(1/2)*1.5*10^3*0.1^2 - 0.36*0.22*9.8*L*cos60 = 0.36*9.8*L*sin60
L = 2.18 m
the block stops at a distance 2.18 m up the incline
==============================
initial energy of the system Ei = 0
final energy of the system Ef = (1/2)*m1*v^2 + (1/2)*m2*v^2 - m2*g*h
work done by friction Wf = -uk*m1*g*h
Ei + Wf = Ef
0 - uk*m1*g*h = (1/2)*m1*v^2 + (1/2)*m2*v^2 - m2*g*h
-0.24*3*9.8*1.3 = (1/2)*3*v^2 + (1/2)*5*v^2 - 5*9.8*1.3
speed of ball = 3.69 m/s <<<-----------ANSWER
DONE please check the answer. any doubts post in comment box
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