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Question

ACROBAT AaBbceDk AaBbCt Aabbc AaB AaBbo Normal 1 No Spac. Heading 1 Heading 4 TaleSubtitle Subtle Em.. Emphasis Intense E. Strong Quate Intens Styles Page 10 of 11 PART III: In-lab problem solving 1. Consider the following diagranm 5 cm A light ray leaves point A reflects from the mimor and reaches point B. How far from the top edge of the mirror does the ray strike the mirror? 10 cm 15 cm 15 cm A 4.5 m wide swimming pool is filled to the top. The bottom of the pool is completely shaded when the sun is 23 degrees above the horizon. 2. Draw a diagram showing the ray from the sun, its refraction, when the pool is a. first shaded. b. How deep is the pool? (n 1.33) 3. A 2.0 cm tall object is 15 cm in front of a converging lens whose focal length is 20 cm. a. What is the image distance? b. What is the magnification? c. What is the height of the image? hp

Explanation / Answer

part 3 )

using lens equation

1/u + 1/v = 1/f

f = 20 cm

u = 15 cm  

v = image distance from lens  

1/v = 1/f - 1/u

1/v = (1/20)-(1/15)

v = -60 cm

part b )

m = -v/u

m = -(-60)/15 = 4

part c )

m = hi/ho

ho = object height = 2 cm

hi = m * ho = 4 *2 = 8 cm

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