LON-GAPA Impulse and Mom × Chegg Study Guided Solutio × | 0 CSecure https://capa

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LON-GAPA Impulse and Mom × Chegg Study Guided Solutio × | 0 CSecure https://capa8.phy.ohio.edu/res/ Megan Michalak(Student- section: 101) Main Menu Contents Grades tumelhs-prob07.problem?symb-uploaded%2fohiou%2f91391804150295a49oucapa2%2fdefault_13500569 Physics 2001/Spring 2018 l Messages Courses Help Logout Course Contents» * Assignment 8 Impulse and Momentum of a Bike Rider TimerNotes EvaluateFeedback PrintInfo Impulse and Momentum of a Bike Rider Due in 12 hours, 7 minut A 76.0 kg rider sitting on a 8.5 kg bike is riding along at 9.5 m/s in the positive direction. The rider drags a foot on the ground and slows down to 5.9 m/s still in the positive direction. What is the change in momentum of the rider and bike? Tries 0/10 Tries 0/10 Tries 0/10 Submit Answer What is the impulse delivered by the ground to the rider's foot? What force is acting on the bike and rider if slowing down took 15.2 seconds? And, how far did the bike and rider travel during these 15.2 seconds? Submit Answer Submit Answer Submi Answer Tries 0/1O his discussion is closed Send Feedback

Explanation / Answer

A.

Momentum is given by:

P = m*v

Change in momentum will be

dP = Pf - Pi

dP = m*(Vf - Vi)

m = 76 + 8.5 = 84.5 kg

vi = 9.5 m/sec

vf = 5.9 m/sec

So,

dP = 84.5*(5.9 - 9.5)

dP = -304.2 kg-m/sec

Part B.

Change in momentum = Impulse

Impulse = -304.2 kg-m/sec

Part C.

F = Impulse/Time

F = -304.2/15.2

F = -20.01 N

Part D.

acceleration = F/m

a = -20.01/84.5

a = -0.237 m/sec^2

Now using equation

v^2 = u^2 + 2*a*d

d = (v^2 - u^2)/(2*a)

d = (5.9^2 - 9.5^2)/(2*(-0.236))

d = 117.46 m

Please Upvote. Let me know if you have any doubt.

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