006 10.0 points A wire with a weight per unit length of 0.071 N/m is suspended d

Question

006 10.0 points A wire with a weight per unit length of 0.071 N/m is suspended directly above a sec- ond wire. The top wire carries a current of 72.8 A, and the bottom wire carries a current of 72.7 A The permeability of free space is 4 x 10 T m/A Find the distance of separation between the wires so that the top wire will be held in place by magnetic repulsion. Answer in units of mm 007 10.0 points What current is required in the windings of a long solenoid that has 1437 turns uniformly distributed over a length of 0.472 m in order to produce inside the solenoid a magnetic field of magnitude 6.95 × 10-5-1.? The permeablity of free space is 1.25664 × 10-6 Till/A. Answer in units of mA

Explanation / Answer

006)

to be held in air,the net Force on the top wire should be zero

Weight = Magnetic force

m*g = mu_o*i1*i2*l/(2*pi*d)

m is the mass of the wire

i1 = 72.8 A

i2 = 72.7 A

l is the length of the wire

d is the distance of seperation between the wires

then

m*g = mu_o*i1*i2*l/(2*pi*d)

d = (mu_o*i1*i2)/(2*pi*m*g/l)

d = (4*3.142*10^-7*72.8*72.7)/(2*3.142*0.071)

d = 0.0149 m = 1.49 cm

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