ttps//edugen ugen/Iti/main.uni Halliday, Fundamentals of Physics, 10e Heln I (I
ID: 2029780 • Letter: T
Question
ttps//edugen ugen/Iti/main.uni Halliday, Fundamentals of Physics, 10e Heln I (I Unread) PRINTER VERSION 1 BACK Chapter 12, Problem 024 In the figure, a climber with a weight of 490 N is held by a belay rope connected to her dimbing harness and belay device; the force of the rope on her has a line of action through her center of mass. The indicated angles are 50 and g 35 if her feet are on the verge of sliding on the vertical wall, what is te coeffident of static fncaon bet en h dim no shoes and the wall? Units 9)Explanation / Answer
let tension in the cable is T and reaction force on the leg is F.
at the verge of slipping down, friction force is acting upward.
let friction coefficient be k.
then friction force=k*F
balancing total forces in horizontal direction:
T*sin(phi)=F
==>F=0.57358*T…(1)
balancing total forces in vertical direction:
T*cos(phi)=weight-friction force
==>T*cos(35)=490-k*0.57358*T
==>k=(490-0.81915*T)/(0.57358*T)…(2)
balancing torque about the shoes,
T*cos(phi)*L*sin(theta)+T*sin(phi)*L*cos(theta)=weight*L*sin(theta)
==>T*sin(50)*cos(35)+T*sin(35)*cos(50)=490*sin(50)
==>T=376.8 N
using value of T in equation 2,
k=0.8391
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