(3%) Problem 13: An object is placed a distance do in front of a concave mirror

Question

(3%) Problem 13: An object is placed a distance do in front of a concave mirror with a radius of curvature r = 11 cm. The image formed has a magnification of M = 3.6. 50% Part (a) Write an expression for the object's distance, do Grade Summary Deductions Potential 0% 100% 789 HOME Submissions Attempts remaining: Z % per attempt) detailed view 0 END BACKSPACE DEL CLEAR Submit Hint I give up! Hints: 0% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback 50% Part (b) Numerically, what is the distance in cm?

Explanation / Answer

radius of curvature R = 11 cm

magnification M = di/d0 = 3.6

di = 3.6*d0

from mirror eqaution

1/d0 + 1/di = 2/R

1/d0 + 1/(Md0) = 2/R

1/d0*(1 + 1/M) = 2/R

(1/d0) ( M+1)/M = 2/R

1/d0 = 2M/(R*(M+1))

d0 = R*(M+1)/(2M)

d0 = (R/2)*(1 + 1/M)

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part(b)

d0 = (11/2)*(1 + 1/3.6)

d0 = 7.03 cm

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