5.3.8. The Rapid Rotor amusement ride is spinning fast enough that the floor ben

Question

5.3.8. The Rapid Rotor amusement ride is spinning fast enough that the floor beneath the rider drops away and the rider remains in place. If the Rotor speeds up until it is going twice as fast as it was previously, what is the effect on the frictional force on the rider? Central axis a) The frictional force is reduced to one-fourth of its IF previous value. b) The frictional force is the same as its previous value c) The frictional force is reduced to one-half of its previous value. d) The frictional force is increased to twice its previous value. e) The frictional force is increased to four times its previous value.

Explanation / Answer

rider is in equilibrium wrt to ride,

so In vertical, Fnet = 0

f - Fg = 0

f = Fg (Condition for equilibrium)

hence changing angular speed will not change friction force.

Ans:(b)

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