An electric field of magnitude 5310 N/C is applied along the x axis. 1)Calculate

Question

An electric field of magnitude 5310 N/C is applied along the x axis.

1)Calculate the electric flux through a rect- angular plane 0.157 m wide and 0.81 m long if the plane is parallel to the yz plane.
Answer in units of N · m2/C.

2)Calculate the electric flux through the same rectangle if it is parallel to the xy plane.
Answer in units of N · m2/C.

3)Calculate the electric flux through the same rectangle if it now contains the y axis and its normal makes an angle of 41? with the x axis.
Answer in units of N · m2/C.

Explanation / Answer

flux= dot product of electric field and area= EAcos where is the angle made by the electric field with the area vector

area vector is perpendicular to the plane of the surface

1) =0 since area vector is along x axis and electric field is also along x axis

flux=5310*.157*.81 (1)=675.2727 Nm^2/C

2)=90 implies cos=0

hence flux=0

3)=41

flux = 5310 *.157*.81 cos 41 =509.63 Nm^2/C

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