<p>1. Jill is farsighted and cannot see objects clearly that are closer to the e

Question

<p>1. Jill is farsighted and cannot see objects clearly that are closer to the eye than 80.0 cm. What is the focal length of the contact lenses that will enable her to see objects at a distance of 25.0 cm from her eyes?</p>
<p>&#160;</p>
<p>2. The focal lengths of the objective and eyepiece in a compound microscope are 0.50 cm and 2.00 cm, respectively. An object is placed at a distance of 0.52 cm from the objective. If the final image seen by the eye is at a distance of 25 cm from it, what is the magnification?</p>
<p>3. The distance between the object and the eyepiece of a compound microscope is 25.0 cm. The focal length of its objective lens is 0.200 cm and the eyepiece has a focal length of 2.60 cm. What is the total magnification of the microscope when used by the person of normal eyesight?</p>

Explanation / Answer

The near point of the Jill q = -25 cm object distance p = 80cm lens equation: 1/p +1/q = 1/f 1/f = 1/80 + 1/-25 = 1/f f = P[q/P+q] =36.36 cm

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