two equal forces of 5N are applied on an object of mass m=1 kg, with angles of 3

Question

two equal forces of 5N are applied on an object of mass m=1 kg, with angles of 30 degree and 45 with respect to a coordinate system shown in the figure below.
a) write down the x and y components of each force.b) calculate the net force (magnitude) on the object.
c) calculate the direction of the total force.
d) calculate the acceleration of the object (magnitude and direction) along the x- direction

my diagram its kinda of missed up soryy, but there is only 2 angles. the right one is 35 and the left one is 45 and there is a box in the middle which it says m.

Explanation / Answer

Forces in the x direction: Left side: -5*cos(45°) = -3.54 N Right side: 5*cos(35°) = 4.10 N ------------------------- Forces in y direction: Left side: 5*sin(45°) = 3.54 N Right side: 5*sin(35°) = 2.87 N ================================ b.) Net force: x direction: 4.10 - 3.54 = .56 N -------------------------- y direction: 3.54 + 2.87 = 6.41 N ------------------------ Magnitude = sqrt(x^2 + y^2) = sqrt(.56^2 + 6.41^2) = 6.43 N =========================== c.) Direction: tan(angle) = 6.41 / .56 arctan(6.41/.56) = angle angle = 85° above +x axis ========================== d.) acceleration along x-axis: F = m*a since you are concerned only with the x direction you will use only the force in the x-direction. .56 = m * a a = .56 / m Let me know if any of this is unclear to you.

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